Question

Calculate the number of atoms present in one gram of gold.

Answer 1

Atomic mass of gold (Au) = 198 g

Number of atom present in 198 gram of Au or one mole of Au =6.022 × 10^23

Number of atom present in 1 gram of Au is

= 6.022×10^23/198
=0.03041 ×10^23
=3.041×10^21 atoms

number of atom's present in 1 gram of Au is 3.041×10^21 atoms

Answer 2

Here's your answer Buddy!

No. of atom present in 1g of gold (Au) =

Given Mass/Molar Mass ×Avagadro no.

= 1/198 × 6.022×10²³

=3.04×10²¹ atoms

Hope it's helpful! ヾ(❀╹◡╹)ﾉﾞ❀~