Calculate the number of atoms present in one gram of gold.
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Answered by
18
Atomic mass of gold (Au) = 198 g
Number of atom present in 198 gram of Au or one mole of Au =6.022 × 10^23
Number of atom present in 1 gram of Au is
= 6.022×10^23/198
=0.03041 ×10^23
=3.041×10^21 atoms
number of atom's present in 1 gram of Au is 3.041×10^21 atoms
Number of atom present in 198 gram of Au or one mole of Au =6.022 × 10^23
Number of atom present in 1 gram of Au is
= 6.022×10^23/198
=0.03041 ×10^23
=3.041×10^21 atoms
number of atom's present in 1 gram of Au is 3.041×10^21 atoms
Answered by
12
Here's your answer Buddy!
No. of atom present in 1g of gold (Au) =
Given Mass/Molar Mass ×Avagadro no.
= 1/198 × 6.022×10²³
=3.04×10²¹ atoms
Hope it's helpful! ヾ(❀╹◡╹)ﾉﾞ❀~
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