Question

Calculate the number of atoms present in the following,
(a) 132g CO2(C =12, O=16)

(b) 90 g H2O (H=1, 0=16)

Answer 1

a)CO2=132÷44.01

=2.999

={6.02×10^23}×2.999

=1.8058×10^24

b)H2O=90÷18.02

=4.9944

={6.02×10^23}×4.994

=3.0063×10^24