Calculate the number of atoms present in the following,
(a) 132g CO2(C =12, O=16)
(b) 90 g H2O (H=1, 0=16)
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a)CO2=132÷44.01
=2.999
={6.02×10^23}×2.999
=1.8058×10^24
b)H2O=90÷18.02
=4.9944
={6.02×10^23}×4.994
=3.0063×10^24
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