Question

calculate the number of cacl2 molecules in 0.05 grams​

Answer 1

Answer:

I mole that is 40+71 gm of cacl2 has

$6 \times {10}^{23}$

molecules

so how much will 0.05gm have

it is

$(0.05 \times 6 \times {10}^{23} ) \div 111$

Answer 2

Hope this helps

Mark this as brainliest