calculate the number of calcium ions present in 0.81g of calcium chloride(please tell explanation?)
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Answer: Given 3.2g CaO
atomic mass = 40+16
=56
moles of Ca ion =
56
3.2
=0.057
1 mol = 6.022×10
23
atoms of Ca ion
0.057mol=3.44×10
22
Ca ions
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