Calculate the number of calcium ions present in 222 g of calcium chloride.
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222g of CaCl2
is equal to 2 moles of CaCl2
Therefore, it has 2 moles of Ca2+ as 1 mole of CaCl2 contain one calcium ion
So, no. of atoms of Ca 2+ are 2NA ( NA=6.02×10²³)
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