Question

calculate the number of carbon atom
Present in 6 g of glucose​

Answer 1

Answer:

Answer. Thus number of molecules of carbon in 6.022∗1022 molecules of glucose must be = 6∗(6.022∗1022)=36.132∗1022 atoms of carbon

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Answer 2

Explanation:

glucose= c6h12o6=72+12+96=180gm

here carbo = 72 gm=6mole

number of carbon atom is =6×6.022 ×10^23