Calculate the number of carbon atoms in 18 g of glucose - O 3.61 x 1023 O 7.22 x 1023 O 3.61 x 1022 O None of these
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Molecular formula = C6H12O6 Molar mass = 6 × 12 + 12 × 1 + 16 × 6 = 180g mol^-1 Moles in 18g of sample = 18180 = 0.1 moleSo,moles of carbon present in .
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