Question

Calculate the number of carbon atoms in 76.91g of benzoic acid C6H5COOH

Answer 1

Explanation:

Percentage of carbon in C6H5COOH=(78/116)*100=0.67

Mass of carbon=76.91*0.67=51.52

Answer 2

The number of carbon atoms in 76.91 g of benzoic acid $(C_6H_{5}COOH)$ is $42.16\times 10^{23}$ atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

given mass of benzoic acid = 79.61 g

Molar mass of benzoic acid $(C_6H_{5}COOH)$ = 122.12 g/mol

Putting in the values we get:

$\text{Number of moles}=\frac{79.61g}{122.12g/mol}=0.6519moles$

1 mole of benzoic acid $(C_6H_{5}COOH)$ contains = 7 mole of carbon

1 mole of carbon contains = $6.023\times 10^{23}$ atoms

7 mole of carbon contains = $\frac{6.023\times 10^{23}}{1}\times 7=42.16\times 10^{23}$ atoms

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