calculate the number of carbon, oxygen, hydrogen in 18g of glucose (hint:molecular mass of glucose 180amu )
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Answer:
Molecular formula =C
6
H
12
O
6
Molar mass =6×12+12×1+16×6=180gmol
−1
Moles in 18g of sample=
180
18
=0.1mole
So,moles of carbon present in sample=0.1×6=0.6
Moles of hydrogen=0.1×12=1.2
Moles of oxygen=6×0.1=0.6
No. of atoms present in carbon=0.6×6.022×10
23
=3.6×10
23
No. of atoms present in hydrogen=1.2×6.022×10
23
=7.2×10
23
No. of atoms present in oxygen=0.6×6.022×10
23
=3.6×10
23
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