Chemistry, asked by sarah180, 10 months ago

Calculate the number of chloride ions in 25.0g of calcium chloride.

Answers

Answered by sandeeppatole
0

Answer:

So, molarity is defined as the number of moles of solute present in

1 L

of solution. For the first solution, you have aluminium chloride,

AlCl

3

, as the solute and a volume of

10

cm

3

1 dm

3

10

3

cm

3

=

10

2

.

dm

3

This means that the first solution will contain

10

2

dm

3

3.3

10

2

.

moles AlCl

3

1

dm

3

=

3.3

10

4

.

moles AlCl

3

Now, every mole of aluminium chloride that dissociates in aqueous solution produces

one mole of aluminium cations,

1

×

Al

3

+

three moles of chloride anions,

3

×

Cl

This means that for every

1

mole of aluminium chloride dissolved to make this solution, you will end up with

3.3

10

2

moles AlCl

3

3 moles Cl

1

mole AlCl

3

=

9.9

10

4

.

moles Cl

Now do the same for the calcium chloride solution. You will have

20

cm

3

1 dm

3

10

3

cm

3

=

2.0

10

2

.

dm

3

This means that the solution contains

2.0

10

2

dm

3

5.0

10

2

.

moles CaCl

2

1

dm

3

=

1.0

10

3

.

moles CaCl

2

Now, every mole of calcium chloride that dissociates in aqueous solution will produce

one mole of calcium actions,

1

×

Ca

2

+

two moles of chloride anions,

2

×

Cl

This means that the second solution will contain

1.0

10

3

moles CaCl

2

2 moles Cl

1

mole CaCl

2

=

2.0

10

3

.

moles Cl

Therefore, you can say the solution B) will contain the higher concentration of chloride anions, since

2.0

10

3

.

moles Cl

>

9.9

10

4

.

moles Cl

Use the same approach to calculate the number of moles of chloride anions present in solutions C) and D) and compare all four solutions to find the answer.

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