calculate the number of chlorine ions in 75g of aluminum chloride?
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Answer:
Explanation:
Formula of Aluminium Chloride is AlCl3
Molar mass of AlCl3 is 133.5g
Therefore there are 3 moles of chlorine atoms in one mole of AlCl3
3 moles = 18.066 * 10^23 atoms
(Given Mass/Molar mass) = (No of atoms in given mass/No of atoms in 1 mole)
So, the number of chlorine ions in 75g of aluminium chloride is:-
75/133.5 = no of atoms/18.066 * 10^23
no of atoms = (75 * 18.066 * 10^23)/(133.5)
= 1.011 * 10^24 atoms (approx)
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