Calculate the number of chromium atom in 1.47 g of pota ium dichromate (K2Cr2O7) [Atomic mass: K=39, Cr=52, O=16].
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Answers
Answer:
The number of chromium atoms in 1.47 grams of potassium dichromate
= 6.022×10²¹ atoms.
The chemical formula of potassium dichromate = K₂Cr₂O₇
Potassium dichromate has 2 atoms of chromate atoms in each molecule.
The atomic mass of potassium = 39g/molg/mol
The atomic mass of chromium= 52g/molg/mol
The atomic mass of oxygen = 16g/molg/mol
Hence, the molecular mass of potassium dichromate = (39×2)+(52×2)+(16×7)
= 78+104+112
= 294g/molg/mol
one mole of potassium dichromate has 2 moles of chromium atoms in it,
so, 294-grams K₂Cr₂O₇ has 104 grams of chromium atom.
∴ amount of chromium atom in one gram K₂Cr₂O₇ = \frac{104}{294}
294
104
= 0.35 gram
Therefore the amount of chromium in 1.47 grams of K₂Cr₂O₇ = 1.47×0.354
= 0.52 grams
Number of moles of chromium atoms here = \frac{0.52}{52}
52
0.52
= 0.01 moles
∴ number of chromium atoms in 1.47 grams of potassium dichromate=
= 0.01×6.022×10²³
= 6.022×10²¹ atoms.
Answer:
Calculate the number of chromium atom in 1.47 g of pota ium dichromate (K2Cr207) [Atomic mass: K-39, Cr=52, O=16].
Molecular mass of K2 Cr 2 07
= 2×39 + 2×52 + 16×7
= 78+104+112
= 294
There are number of Cr atom in 294 gm. K2 Cr2 07 = 2×6.022×10²3
No of Cr atom in 1.47 gm K2 Cr2 07
= 2×6.022×102³x1.47 / 294
= 6.022×10²¹ atoms
Explanation:
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