calculate the number of cl minus ions in 100 ml of 0.001M hcl solution?
Answers
Answer:
0.001M HCl of 100mL will have 0.001*0.1 moles = 10^-4 moles
1 mole of HCl contains 6*10^23 Cl- ions
Thus 10^-4 moles of will contain 6*10^19 number of Cl ions
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Answer:
The number of chloride ions in 100 ml of 0.001 M HCl solution are 6.022\times 10^{19}6.022×10
19
.
Solution : Given,
Volume of HCl solution = 100 ml
Molarity of solution = 0.001 mole/L
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
Molarity=\frac{\text{ Moles of solute}\times 1000}{\text{ Volume of solution in liter}}Molarity=
Volume of solution in liter
Moles of solute×1000
Now put all the given values in this formula, we get moles of solute.
0.001mole/L=\frac{\text{ Moles of solute}\times 1000}{100L}0.001mole/L=
100L
Moles of solute×1000
\text{ Moles of solute}=0.0001moles=10^{-4}moles Moles of solute=0.0001moles=10
−4
moles
The moles of HCL = 10^{-4}moles10
−4
moles
1 mole of HCl Consists of 1 mole of Cl^-Cl
−
ions and 1 mole of H^+H
+
ions.
As, 1 mole of HCl contains 6.022\times 10^{23}6.022×10
23
chloride ions
10^{-4}moles10
−4
moles of HCl contains (6.022\times 10^{23})\times (10^{-4})=6.022\times 10^{19}(6.022×10
23
)×(10
−4
)=6.022×10
19
chloride ions
Therefore, the number of chloride ions in 100 ml of 0.001 M HCl solution are 6.022\times 10^{19}6.022×10
19