calculate the number of constituent atoms in 53 gram of Na2CO3
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atomic mass of Na=23
atomic mass of C=12
atomic mass of O=16
number of constituents = given mass/molar mass* Nₐ
= 106/53*Nₐ
= 2Nₐ
12.044*10²³
atomic mass of C=12
atomic mass of O=16
number of constituents = given mass/molar mass* Nₐ
= 106/53*Nₐ
= 2Nₐ
12.044*10²³
meher10:
could you pls elaborate it a bit
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