calculate the number of constituent atoms in 53g of Na2CO3
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Answered by
305
Avagadro's constant states that 1 mole of any substance has 6.022 × 10²³ molecules/atoms.
Find the number of moles of 53 g of Na2CO3:
molar mass Na2CO3 = 23 × 2 + 12 + 16 × 3 = (46+12+48) = 106
moles = mass/molar mass
= 53/106
= 0.5 moles
1 mole = 6.022 ×10²³ atoms
Then 0.5 moles = 6.022 × 10²³ × 0.5 atoms
= 3.011 × 10²³ atoms of Na2CO3
Find the number of moles of 53 g of Na2CO3:
molar mass Na2CO3 = 23 × 2 + 12 + 16 × 3 = (46+12+48) = 106
moles = mass/molar mass
= 53/106
= 0.5 moles
1 mole = 6.022 ×10²³ atoms
Then 0.5 moles = 6.022 × 10²³ × 0.5 atoms
= 3.011 × 10²³ atoms of Na2CO3
Answered by
36
Answer: The no.of atoms = given mass/molar mass × Avogadro no
Molar mass = 106
=53/106×6.022×10^23
=3.011×10^23
Explanation:
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