Question

calculate the number of degrees of freedom for 7 moles of a triatomic gas at ntp

Answer 1

Explanation:

Moles of He =

4

2

=

2

1

Molecules =

2

1

×6.02×10

23

= 3.01×10

23

As there are 3 degrees of freedom corresponding of 1 molecule of a monatomic gas.

∴ Total degrees of freedom = 3×3.01×10

23

=9.03×10

23

Answer 2

Explanation:

The general epression for degree of freedom is DOF=3N−n

here, DOF means degree of freedom, N is number of particle, and n is the number of holonomic constraints.

for a triatomic molecule, the number of particle is 3 and since the separation between three atoms are fixed so, the number of constraints is 3.

hence, DOF=(3×3)−3

DOF=9−3

DOF=6