calculate the number of elections in 100 grams of co2
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given mass ×avogadro no. / molecular mass
100×6.022 ×10^23/ 44
100×6.022 ×10^23/ 44
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6 ele of C + 16 of O2 = 22 ele per molecule of CO2
6.022 x 10²³ molecule = 44g mol⁻¹
moles of CO2 = 100 / 44
= 2.27 mol
electron = 22 x 2.27 x 6.022 x 10²³
electron will be = 3x 10²⁵
6.022 x 10²³ molecule = 44g mol⁻¹
moles of CO2 = 100 / 44
= 2.27 mol
electron = 22 x 2.27 x 6.022 x 10²³
electron will be = 3x 10²⁵
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