Question

calculate the number of elections in 100 grams of co2

Answer 1

given mass ×avogadro no. / molecular mass
100×6.022 ×10^23/ 44

Answer 2

6 ele of C + 16 of O2 = 22 ele per molecule of CO2

6.022 x 10²³ molecule = 44g mol⁻¹

moles of CO2 = 100 / 44

= 2.27 mol

electron = 22 x 2.27 x 6.022 x 10²³
electron will be = 3x 10²⁵