Calculate the number of electron present in d-orbital of Cu++and Fe++ ions.
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Answer:
9 for cu++ and 6 for fe ++
Explanation:
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Answer:
Cu=29=[Ar] 4s1 3d10
Cu++=27=[Ar] 4s0 3d9
unpaired electrons are one
Fe=26=[Ar] 4s2 3d6
Cu++=27=[Ar] 4s0 3d6
unpaired electrons are four
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