Question

calculate the number of electrons and protons and neutrons in phosphide ion p+ ,Phosphonium ion ph4+ and phosphate ion po4 3-,atomic number of p is 15 and h is 1 and o is 8 mass no of p is 31 and h is 1 and o is 16​.​

Answer 1

[Number of Neutrons=mass no. - protons]

(I) P^-3

Protons =15

Electrons=15+3=18

Neutrons=31-15=16

(II)(PH4)^1

Protons=15+4=19

Electrons=19-1=18

Neutrons=31+4-19=16

(III)(PO4)^-3

Protons=15+32=47

Electrons=47+3=50

Neutrons=31+16x4-47=48

Answer 2

Answer:

following answer attached