calculate the number of electrons and protons and neutrons in phosphide ion p+ ,Phosphonium ion ph4+ and phosphate ion po4 3-,atomic number of p is 15 and h is 1 and o is 8 mass no of p is 31 and h is 1 and o is 16.
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[Number of Neutrons=mass no. - protons]
(I) P^-3
Protons =15
Electrons=15+3=18
Neutrons=31-15=16
(II)(PH4)^1
Protons=15+4=19
Electrons=19-1=18
Neutrons=31+4-19=16
(III)(PO4)^-3
Protons=15+32=47
Electrons=47+3=50
Neutrons=31+16x4-47=48
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