Question

calculate the number of electrons consituting one columb of charge

Answer 1

Answer:

q=ne

1=n*1.6*10-19

n=6.278*10 rase to18

so ans is 6.2 into 10 rase to power 18

hope so helpful

Answer 2

Answer:

$charge \: on \: one \: electron \\ \: = 1.6 \times {10}^{ - 19}$

$if \: charge(q) \: is \: 1$

$no \: of \: electron \: = n$

$q = ne$

$n = \frac{q}{e} \\ \\ n = \frac{1}{1.6 \times {10}^{ - 19} } \\ \\ n = 6.25 \times {10}^{18} electrons$

$hope \: my \: answer \: helps \: you \: buddy$