Question

calculate the number of electrons constituting in the Coulam​

Answer 1

Firstly, it's spelled "coulomb", and not "coulam".

Proceeding to the solution -

we're given that the magnitude of current

(q) = 1C

now, charge on 1 electron (e)

$= 1.6 \times {10}^{ - 19}$

We know that,

$q = ne \\ \\ where \: q = magnitude \: of \: the \:charge \\ n = number \: of \: electrons \: in \: specific \\ magnitude \: of \: charge \\ and \: e = charge \: on \: one \: electron \\ \\ q = ne \\ \\n = \frac{q}{e} \\ \\ n = \frac{1}{1.6 \times {10}^{ - 19} } \\ \\n = \frac{ {1 \times 10}^{19} }{1.6} \\ \\ n = 0.625 \times {10}^{19} \\ \\n = 6.25 \times {10}^{18} \\ \\ \\ hence \: there \: are \: 6.25 \times {10}^{18} electrons \\ in \: one \: coulomb \: of \: charge$