Question

Calculate the number of electrons constituting one columb of charge per second through any cross section of a conductor

Answer 1

Answer:

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Answer 2

$charge \: on \: one \: electron \\ \: = 1.6 \times {10}^{ - 19}$

$if \: charge(q) \: is \: 1$

$no \: of \: electron \: = n$

$q = ne$

$n = \frac{q}{e} \\ \\ n = \frac{1}{1.6 \times {10}^{ - 19} } \\ \\ n = 6.25 \times {10}^{18} electrons$

$hope \: my \: answer \: helps \: you \: buddy$