calculate the number of electrons constituting one coulomb of charge
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Answered by
15
We know that charge is quantised.
So, q = n e
According to the question, q = 1 C
1 e = 1.6 x 10 ^-19
n = q / e = 1/(1.6 x 10^-19) = 6.25 x 10^18 electrons
So, q = n e
According to the question, q = 1 C
1 e = 1.6 x 10 ^-19
n = q / e = 1/(1.6 x 10^-19) = 6.25 x 10^18 electrons
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Answered by
3
We know that Q=ne
where Q= Charge
n=Number of electrons
e=Charge of an electron(1.6*10^-19:10 to the power minus 19)
Using this,
1C=n*1.6*10^-19
1/1.6*10^-19=n
10*10^18/1.6=n
6.25*10^18=n
Thus there are 6.25*10^18 electrons in 1C of charge.
Hope you got the answer!
where Q= Charge
n=Number of electrons
e=Charge of an electron(1.6*10^-19:10 to the power minus 19)
Using this,
1C=n*1.6*10^-19
1/1.6*10^-19=n
10*10^18/1.6=n
6.25*10^18=n
Thus there are 6.25*10^18 electrons in 1C of charge.
Hope you got the answer!
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