calculate the number of electrons constituting one coulomb of charge
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we know that the charge of 1 electron = 1.6 x 10power minus19 coulomb
thus, 1.6 x 10power minus 19C of charge=1 electron.
therefore 1C= 1/1.6 x 10 power minus 19 electrons
= 10 power19/1.6 electrons
= 10 x 10power 18/1.6 electrons
=6.25 x 10 power18 electrons
thus, 1.6 x 10power minus 19C of charge=1 electron.
therefore 1C= 1/1.6 x 10 power minus 19 electrons
= 10 power19/1.6 electrons
= 10 x 10power 18/1.6 electrons
=6.25 x 10 power18 electrons
Answered by
1
HELLO THERE!
By Milikan's Oil Drop experiment, it has been found that the charge of 1 electron is -1.6 x 10⁻¹⁹ Coulomb (C).
Now, -1.6 x 10⁻¹⁹C charge is possessed by 1 electron.
Hence, 1 C charge is possessed by:
[tex] \frac{1}{1.6\times10^{-19}} \\\\=6.25 \times 10^{18} [/tex]
electrons.
HOPE THIS HELPS!
By Milikan's Oil Drop experiment, it has been found that the charge of 1 electron is -1.6 x 10⁻¹⁹ Coulomb (C).
Now, -1.6 x 10⁻¹⁹C charge is possessed by 1 electron.
Hence, 1 C charge is possessed by:
[tex] \frac{1}{1.6\times10^{-19}} \\\\=6.25 \times 10^{18} [/tex]
electrons.
HOPE THIS HELPS!
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