Question

Calculate the number of electrons in 1.8g of Glucose :
$a)5.8 \times {10}^{23} \: \: \: \: \: \: \: \: \: b)5.6 \times {10}^{22}$
(Only Two Options)
Please Tell The No. Of Electrons Not The Atoms....
Your Help Would Be Appreciated And You'll Be Given Marked As The Brainliest If You Answer Correctly And Briefly
Thanks....​

Answer 1

Explanation:

Find the number of moles (n)

n=mass/gram formula mass

=1.8/180

=0.01 mol

Find the number of molecules

no of molecules=n x L[avogadro's constant - 6.02x10^23]

=0.01 x 6.02x10^23

=6.02x10^21

180 g of glucose = 1 mole of glucose= 6.022 X 10^23 molecules of glucose

total electrons in glucose = 6(C) + 12(H)+ 6(O) = 24

1 molecule of glucose contains = 24 electrons

1 mole glucose contains = 24 * NA electrons

NA = Avogadro’s number

then

0.01 mole glucose contains = 24*6.023*10^23*0.01

= 24*6.023*10^21

Answer 2

Explanation:mass of one molecule of glucose=180 a.m.u

mass of one mole of glucose=180g

number of molecules in 180 g of glucose=6.022×10^23(no.of molecules in one mole)

number of molecules in 1.8 g of glucose=6.022×10^23/180×1.8 =6.022×10^21

In one molecule of glucose ,there are 6 carbon,12 hydrogen,6 oxygen atoms.

no. of e- in one atom of carbon=6" " " " " " " hydrogen=1

" " " " " " " oxygen = 8

now, no of electron in 6 carbon atom=6×6=36

no of electron in 12 hydrogen atom =1×12=12

no of e- in 6 oxygen atom=6×8=48

total electrons in one molecule of glucose=36+12+48=96

total electrons in 6.022×10^21 molecules=6.022×10^21×96

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