Question

Calculate the number of electrons in 1.8g of Glucose : $a)5.8 \times {10}^{23} \: \: \: \: \: \: \: \: \: b)5.6 \times {10}^{22}$(Only Two Options)Please Tell The No. Of Electrons Not The Atoms....Your Help Would Be Appreciated And You'll Be Given Marked As The Brainliest If You Answer Correctly And Briefly Thanks....​

Answer 1

Answer:

Option number (1) is correct.

$5.8 \: \times \: {10}^{23} elctrons \: is \: present \: in \: the \: 1.8 \: gram \: of \: glucose.$

Explanation:

Given

Given weight of glucose = 1.8 gram

Molecular weight of glucose (C6H12O6)

=12 × 6 + 1 × 12 + 16 × 6 gram

=72 + 12 + 96 gram

=180 gram

Molecular weight of glucose (C6H12O6)= 180 gram

Number of moles of glucose

$= \frac{given \: weight \: of \: glucose \: }{molecular \: weight \: of \: glucose}$

Number of moles of glucose = 1.8/180 moles

Number of moles of glucose = 1/100 moles

Number of moles of glucose = 0.01 moles

Number of molecules of glucose

$= 0.01 \: \times \: 6 \: \times {10}^{23} \: molecules \: = \: 0.06 \: \times {10}^{23} molecules$

1 atom of carbon contain 6 electrons

Then, 6 atom of carbon contain 36 electrons

1 atom of hydrogen contain 1 electron

Then, 12 atoms of hydrogen contain 12 electrons

1 atom of oxygen contain 8 electrons

Then, 6 atoms of oxygen contain 48 electrons

1 molecule of glucose contains 6 carbon atoms , 12 hydrogen atom and 6 oxygen atom.

1 molecule of glucose contain = ( 36 + 12 + 48 ) electrons

1 molecule of glucose contain ( C6H12O6) = 96 electrons

Then,

$0.06 \times {10}^{23} molecules \:of glucose contains \: = \: 0.06 \times 96 \times {10}^{23} electrons \\ = 5.76 \times {10}^{23} electrons \: = \: 5.8 \times {10}^{23} (approx) \: electrons.$