Question

calculate the number of electrons in one columb of negative charge.. (sum)​

Answer 1

Answer:

Number of electrons = 6.25×10¹⁸ electrons

Explanation:

We know that,

$\boxed{Q=ne}$ where,

Q is the charge

n is the number of electrons

e is the charge of 1 electron

Given that,

Charge = Q = 1C

Charge of 1 electron = e =  1.6×10⁻¹⁹C

Number of electrons = n = ?

Putting these vales in we get,

1 = n * (1.6×10⁻¹⁹)

n = $\frac{1}{1.6*10^{-19} }$

n = 6.25×10¹⁸ electrons