Question

Calculate the number of electrons lose from metal ball it's charge one Colomb

Answer 1

Solution :

We know that,

Charge on 1 electron is $\sf{1.6 \times 10^{-19}\:C}$.

Solving by unitary method:

If the charge on 1 electron is 1.6×10^-19 C, then, the charge on ? electrons is 1 C ?

Therefore,

$\implies$ $\sf{x =\frac{1}{1.6\times {10}^{ - 19}}}$

$\implies$ $\sf{x = 0.625 \times {10}^{ - 19}}$

$\implies$ $\sf{x = 6.25 \times {10}^{ 18}}$

Solving by formula,

$\implies$ $\huge{\boxed{\sf{Q = ne}}}$

Where,

Q $\longrightarrow$ Charge

n $\longrightarrow$ Number of electrons

e $\longrightarrow$ Charge on electron

Now,

$\implies$ $\boxed{\sf{n=\frac{Q}{e}}}$

$\implies$ $\sf{n=6.25 \times 10 ^{18}}$

Hence,

The number of electrons lose from a metal ball, whose charge is 1 C is $\sf{6.25 \times 10^{18}}$

______________

Answered by: Niki Swar, Goa❤️

Answer 2

Explanation:

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Refers with attachment