Question

Calculate the number of electrons moving let second through the filament of a lamp of 100W operating at 200V given charge on electron is : 1.6 × $10{}^-19$

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Answer 1

Q=?

I=0.54A

t=1 sec.

Q=It

Q=0.54×1

=0.54C

number of electrons That Flow in 1 coulomb of charge=1.6×10^-9

number of electrons That Flow in 0.54 coulomb of charge=0.864×10^-9

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Answer 2

★${\bold{\underline{Hey\:Mate}}}$

Here's the Answer ❗

${\bold{\mathbb{\boxed{Concepts \:of\:Electricity}}}}}$

♦Given that

→Power (P) = 100 Watts

→Voltage (V) = 200V

→Time (T) = 1 second

Using the formula ,

P = V × I

100 = 200 × I

tex

I = $\frac{100}{200}$

${\bold{\underline{Current \:=\: 0.5 A }}}$

Now we know that

q = I × t

q = 0.5 × 1 = 0.5 C

${\bold{\underline{Charge \:=\: 0.5 C }}}$

Using concept of quantization of charge

q = n.e

0.5 = n × 1.6 × $10{}^-19$C

n = 0.31 × $10{}^19$

${\bold{\underline{Number\:of\:Electrons\ }}}$ = 0.31 × $10{}^19$

${\huge{\mathtt{Hope\:Helps!}}}$

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