Calculate the number of electrons passing a point in a circuit when there is a current of . a.4.0A for t .60s. b.12mA for 25s
Answers
Answered by
1
a.
n = it / e
= (4 × 60) / (1.6 × 10^-19)
= 1.51 × 10^21 electrons
Number of electrons passing is 1.5 × 10^21
b.
n = it / e
= (12 × 10^-3 × 25) / (1.6 × 10^-19)
= 1.875 × 10^18
Number of electrons passing is 1.875 × 10^18
n = it / e
= (4 × 60) / (1.6 × 10^-19)
= 1.51 × 10^21 electrons
Number of electrons passing is 1.5 × 10^21
b.
n = it / e
= (12 × 10^-3 × 25) / (1.6 × 10^-19)
= 1.875 × 10^18
Number of electrons passing is 1.875 × 10^18
Similar questions