Question

calculate the number of electrons passing through a given point of where 0.28 current is flowing through one wire

Answer 1

0.28A= 0.28 C/s

=0.28× 6.25×10^18

=1.75×10^18 elections per second

Answer 2

Acc. to me,

i=q/t

q=ne

given e=1.6*10^-19C

i=.28

at time t=1 sec

i=ne/t

put the value

0.28=(n*1.6*10^-19)/1

n=0.28/(1.6*10^-19)

n=0.175*10^19 electrons passes in one second

I hope it help