Question

Calculate the number of electrons passing through the wire in one second , if a wire carries a current of 6.4A . The change on each electrons , e = 1.6 × 10^-19 c

Answer 1

Explanation:

we know that current =charge/time

so here I=6.4A and charge (q) =ne where n=number of electrons

again time (t) =1 sec

so applying the above value we get 6.4A =n×1.6×10^-19c/1sec

so by solving we get n= 4×10¹⁹