Question

calculate the number of electrons that flow through a conductor in 1 second to constitute 1 A (charge of electron 1.6 x 10'-19 c)

Answer 1

1 A = 1 C / 1 sec

charge of electron = 1.6 × 10 (-19) C

1 electron = 1.6 × 10(-19) C
1 ÷ 1.6 ×10 (-19) electrons = 1C

hence no. of electron = 1÷ 1.6 × 10 (-19)
= 0.62 × 10 (19)
= 1 × 10 (19) electron

Answer 2

Given that

Charge (Q) = 1 C

Electron (e) = 1.6× 10^-19

Number of electron (n) = ?

Q= ne

1 C = n × 1.6×10^-19 C

n = 1/(1.6×10^-19)

n = 6.25 × 10^18 electron