Question

calculate the number of electrons that would flow per second through the cross section of a wire when 1A current flows in it​

Answer 1

Answer:

0.62x10∧19 electrons

Explanation:

q = it = 1 A x 1s = 1 coulomb

a single electron has a charge of 1.602 × 10∧-19 Coulombs.

number of electrons that would flow  per second through the wire = N

N = 1 ÷ 1.602 × 10∧-19 = 0.62x10∧19 electrons

Answer 2

Answer:

no. of electrons = 6.25 x 10^18

Explanation:

I = Q/t

1A = 1C / 1S

1A = no. of electrons x 1 electron / 1s [ 1C = no. of electrons x 1 electron ]

1A = ne- x 1.6 x 10^-19 / 1s

1A x 1s / 1.6 x 10^-19 = ne-

ne- = 1 / 1.6 x 10^-19

ne- = 0.625 x 10^19

ne- = 6.25 x 10^18