Question

Calculate the number of electrons transferred
to develop 2
coulumb charge​

Answer 1

Answer:

3columb charger

Explanation:

Answer 2

Answer:

One electron possesses a charge of :

e=1.602 \times 10^{-19} \, \, Ce=1.602×10

−19

C

We are given a total of 2 C charge. Let us assume there are n electrons making up that 2 C charge.

We have:

\begin{lgathered}ne = 2 \\ \\ \\ \implies n \times 1.602 \times 10^{-19} = 2 \\ \\ \\ \implies n = \frac{2}{1.602 \times 10^{-19}} \\ \\ \\ \implies \boxed{n \approx 1.248 \times 10^{19}}\end{lgathered}

ne=2

⟹n×1.602×10

−19

=2

⟹n=

1.602×10

−19

2

⟹

n≈1.248×10

19

Thus, there are approximately 1.248 \times 10^{19}1.248×10

19

electrons in 2 coulomb charge.