Question

calculate the number of electrons Travel through a conductor if it carries 5amp of current for 3 milliseconds​

Answer 1

Answer:

Total charge that flows in 2s is given by

q=It=5×2=10C

Now, charge on one electron is given by e=1.6×10

−19

C

N= number of electrons

q=Ne

⟹N=

e

q

⟹N=

1.6×10

−19

10

⟹N=6.25×10

19

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