calculate the number of excess electrons in a body having charge of. -1 coloumb??
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Sol. we know
charge = no. of electrons× charge of electron
=> q = ne
=> n = q/e = 1/1.6×10^-19
=> n = 0.625 × 10¹⁹
=> n = 6.25 × 10¹⁸ electrons
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