Question

Calculate the number of gold atoms present in 0.45g of a gold ring made from 22 carat gold given that the atomic mass of gold is 197 and pure gold is 24 carats

Answer 1

Answer:

If Pure Gold is 24 Carats, it means it is made of 100 % Gold. If so, then 22 carats means = 10024×22=91.67 %

Hence, the weight of Gold in 0.45 g of a 22 carat gold is = 91.67100×0.45=0.41

Now, since 1 mole or 197 g of Gold has 6.022 x 1023 atoms in it. The number of atoms in 0.41 g of gold will be =

6.022×1023 197 g×0.41 g =1.25×10216.022×1023 197 g×0.41 g =1.25×1021

Answer 2

Answer:

1.25 × 1021 is the answer of the above questions