Question

Calculate the number of gold atoms present in 98'g of gold atomic mass of gold 197gram

Answer 1

Answer:

3.0115 x 10^23

Explanation: given,

mass number of gold= 197

density = 19.7

avogadro's number= 6.023 x 10^23

number of moles of gold = given mass / atomic mass

                                          = 98/197

                                         = 0.5 mol

thus number of gold atoms = no of moles  x  avogrado's number

                                            = 0.5 x 6.023 x 10^23

                                           = 3.0115 x  10^23

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