Calculate the number of gram atoms present in the following masses:-
i) 64g of oxygen
ii)140g of nitrogen
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1) 64gm of oxygen :-
no. of moles = given mass ÷ molecular mass.
=. 64÷ 32
=. 2 moles.
so, total atom of oxygen =(6.022×10^23 × 2) atom
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2) 140gm of Nitrogen:-
no. of moles :- given mass ÷ molecular mass.
= 140÷ 14
= 10 moles
so, total atom of nitrogen =(6.022×10^23× 10) atom.
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