Calculate the number of gram molecule present in and number of mole present in 12.044×10^25 molecules of CO2
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Answer:
see the image
Explanation:
You need to appreciate the factor that 6.022*10^23 molecules=16g
therefore,
6.022*10^23=16g
therefore,
12.044*10^25 molecules is equivalent to what mass
(12.044*10^23)*16/(6.022*10^23)
=>3200g
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