Question

Calculate the number of gram molecules of water in beaker containing 576 gms. of water *
a. 16
b. 32
c. 8
d. 64​

Answer 1

Answer:

<br> (b) number of gram molecules of water in a beaker containing 576 g of water. ∴18g of water = 1 gram molecule.

Explanation:

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Answer 2

The number of gram molecules of water in a beaker containing 576 g of water is (b) 32.

Given: A beaker containing 576 g of water.

To Find: The number of gram molecules of water in a beaker containing 576 g of water.

Solution:

• We need to use the concept of stoichiometry to solve this numerical.

We know that,

• 1 mole of a compound = molecular mass of the compound

• 1 mole of a compound = 1 gram-molecule of the compound

Coming to the numerical, we have,

The mass of water given = 576 g

The molecular mass of water (H2O) = ( 2 × 1 ) + 16

                                                            = 18 g

So, from stoichiometry, we can say that;

1 mole of H2O = 18 g of H2O = 1 gram-molecule of H2O

⇒ 18 g of H2O = 1 gram-molecule of H2O

⇒  1 g of H2O = ( 1 / 18 ) gram-molecule of H2O

⇒ 576 g of H2O = ( 576 / 18 ) gram-molecule of H2O

                           = 32 gram-molecule of H2O

Hence, the number of gram molecules of water in a beaker containing 576 g of water is (b) 32.

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