Question

Calculate the number of grams of magnesium sulphate to prepare 450ml of 2.25m solution

Answer 1

Answer:

Molarity = w2 × 1000 / V × M2

where, w2 = weight of solute requires in g

M2 = Molar mass of solute in g

V = Volume of Solution in ml

m = w2 × 1000/ 450 × 120

2.25 = w2 ×1000 / 450 × 120

w2 = 121.5g of MgSO4 required

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