Question

Calculate the number of H atoms in 5.35g of NH4Cl

Answer 1

Answer:

The total number of hydrogen atoms in 5.35gram of ammonium chloride is 2.41×10²³.

Explanation:

Given molecule = NH₄Cl

the atomic mass of nitrogen = 14 $g/mol$

the atomic mass of hydrogen = 1 $g/mol$

the atomic mass of chlorine = 35.5 $g/mol$

NH₄Cl or ammonium chloride has one nitrogen atom, 4 hydrogen atoms, and one chlorine atom in it.

Hence molar mass of ammonium chloride = 14+(4×1)+35.5 =53.5 $g/mol$

Here, the given mass of ammonium chloride = 5.35$g$

Number of moles of ammonium chloride present = $\frac{5.35}{53.5} = 0.1 moles$

One mole of ammonium chloride has 4 moles of hydrogen atoms in it,

so, 0.1 moles have 0.4 moles of hydrogen atoms in it.

one mole = 6.022×10²³ atoms

here, the total number of hydrogen atoms in 5.35gram of ammonium chloride = 6.022×10²³×0.4 = 2.41×10²³ atoms.