Calculate the number of hydrogen atoms present in 0.342g of sucrose(C12H22O11).
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Molar mass of C12H22O11 = 12x12 + 22x1 + 11x16 = 144 + 22 + 176
= 342 g/mol
342g contains 22 H atoms
1g contains 22/342 H atoms
0.342 g contains (22/342) x 0.342 = 22 x 10⁻³ H atoms
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= 342 g/mol
342g contains 22 H atoms
1g contains 22/342 H atoms
0.342 g contains (22/342) x 0.342 = 22 x 10⁻³ H atoms
if it helped
plz mark it as brainliest , i need it early
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