Question

Calculate the number of hydrogen atoms present in 0.5 mole of ethanol
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Answer 1

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Answer 2

Answer:

NA=6.02214076×1023 mol−1≈6.022×1023 mol−1

Each hydrogen molecule has two hydrogen atoms, therefore

n(H)=2⋅n(H2)

N(H)=n(H)⋅NA

N(H)=2⋅n(H2)⋅NA

N(H)=2×0.5 mol×6.022×1023 mol−1

N(H)=6.022×1023.

Explanation: