calculate the number of hydrogen atoms present in 2.30 g of c2h5oh
Answers
Answered by
0
C2H5OH is 46moles
here, moles present in 2.30gm is (2.30/46)= 0.05moles
and we have 6moles of H in 1 mole of C2H5OH
moles of h present in 0.05moles of C2H5OH is (6*0.05)Moles
so number of Hatoms in (6*0.05)Moles= (6*0.05*6.023*10^23) atoms
which equals to 3.794*10^24 Atoms. (:
here, moles present in 2.30gm is (2.30/46)= 0.05moles
and we have 6moles of H in 1 mole of C2H5OH
moles of h present in 0.05moles of C2H5OH is (6*0.05)Moles
so number of Hatoms in (6*0.05)Moles= (6*0.05*6.023*10^23) atoms
which equals to 3.794*10^24 Atoms. (:
kdas56006:
but right answer is 1.80x10^23
someone do it correctly
oops
hii
plz solve in correct manner
Okay Let me Think
hiii
do u get answer
I solved How i typed it above is it wrong? where did you check the answer???
okaysmall mistake ruined the answer just solve this you get the answer (6*0.05*6.023*10^23) the second last line i made the mistake in the calculation there. process is okay.
Similar questions