Question

Calculate the number of hydroxide ions present in 1.75 g of ammonium hydroxide

Answer 1

Explanation:

So 1 mole of NaCl weighs 58.5g. So now we need to convert grams into moles by dividing mass in grams by the mass of 1 mole. This means that in 1dm3 of solution there must be 1 mole of sodium ions. The number of particles in 1 mole is given by the Avogadro Constant which is equal to 6.02x1023mol−1 .

Answer 2

The number of hydroxide ions present in given amount of ammonium hydroxide are $3.011\times 10^{22}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ammonium hydroxide = 1.75 g

Molar mass of ammonium hydroxide = 35 g/mol

Putting values in above equation, we get:

$\text{Moles of ammonium hydroxide}=\frac{1.75g}{35g/mol}=0.05mol$

1 mole of ammonium hydroxide produces 1 mole of ammonium ions and 1 mole of hydroxide ions

According to mole concept:

1 mole of an ionic compound contains $6.022\times 10^{23}$ number of ions

So, 0.05 moles of ammonium hydroxide will contain = $(1\times 0.05\times 6.022\times 10^{23}=3.011\times 10^{22}$ number of hydroxide ions

Learn more about mole concept and number of moles:

https://brainly.com/question/10982990

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