Calculate the number of images formed of an object, placed between
two parallel mirrors separated by 28 cm.
and also state the explanation...
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these two mirrors is 'd'. Let number of images formed are 'n'.Here n is a time dependent quantity. Let at t = T1 ,we placed an object O between the mirrors. At t = T2 , we observed the images formed.Distances of object from mirror-1 and mirror-2 are 'a' and 'b' respectively.Now, let us count number of images 'n' formed in mirror-1 :Time taken by light to travel from object to mirror is distance/speed = a/ca aa / // c cc , where c is speed of light in air. So, time taken by light to come back to the object = 2a/c2a/c 2a/c2a/c2a/c2a/c . Hence, time taken to form first image is = 2a/c.2 22 a aa / // c cc . .. To form second image in mirror-1 after first, light have to travel from object to mirror-2 and then back to mirror-1 and finally from mirror-1 to object. So total distance = b+b+a+a=2(a+b).b+b+a+a=2(a+b) b+b+a+a=2(a+b).b+b+a+a=2(a+b)b+b+a+a=2(a+b).b+b+a+a=2(a+b) . .. So time taken to form second image after the first one =2(a+b)/c=2(a+b)/c. 2(a+b)/c=2(a+b)/c
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