Question

Calculate the number of ion present in 0.01g of Aluminum oxide Atomic mass of Aluminum is 27 u

Answer 1

i think answer should be one u

Answer 2

Molar mass of Al2O3=102 g

102 give of Al2O3 contain =2*6.022*10^23 Al3+ ions

Thus

0.01 g of Al2O3 contain=

[ (2*6.022*10^23) *0.01]/102

=0.00118*10^23 Al3+ ions